Year 8 - Circles - Free practice

Year 8 Circles Worksheets & Practice Tests

Area and circumference - the full Year 8 circle skill set.

Quick answer

How do you find the circumference and area of a circle?

Use the formulas C=2πrC = 2\pi r (or πd\pi d) for circumference and A=πr2A = \pi r^2 for area, where rr is the radius and dd is the diameter. For example, a circle with radius 5 cm has circumference 2π(5)≈31.422\pi(5) \approx 31.42 cm and area π(5)2≈78.54\pi(5)^2 \approx 78.54 cm².

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Six questions across Foundation, Standard and Extension, with full worked solutions, written to the Australian Curriculum.

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Worked examples

Year 8 circles: worked examples

Three examples, from a standard question to a worded problem. Have a go at each one before you open the solution.

  1. Example 1 · Circumference and area from a radius

    A circle has a radius of 99 cm. Find its circumference and area. Give both answers correct to one decimal place.

    Show worked solution

    Key idea: Circumference C=2πrC = 2\pi r and area A=πr2A = \pi r^2, where rr is the radius.

    1. Write the radius: r=9r = 9 cm.
    2. Find the circumference:
      C=2πr=2×π×9=18π≈56.5 cmC = 2\pi r = 2 \times \pi \times 9 = 18\pi \approx 56.5 \text{ cm}
    3. Find the area:
      A=πr2=π×92=81π≈254.5 cm2A = \pi r^2 = \pi \times 9^2 = 81\pi \approx 254.5 \text{ cm}^2

    Answer: Circumference ≈56.5\approx 56.5 cm, Area ≈254.5\approx 254.5 cm2^2

  2. Example 2 · Area of a composite shape (semicircle and rectangle)

    A shape is made from a rectangle and a semicircle. The rectangle is 1010 cm long and 66 cm wide. The semicircle sits on top of one of the 66 cm sides, with that side as its diameter. Find the total area of the shape, correct to one decimal place.

    Show worked solution

    Key idea: The total area is the area of the rectangle plus the area of the semicircle. The semicircle has diameter 66 cm, so its radius is 33 cm.

    1. Find the radius of the semicircle: r=6÷2=3r = 6 \div 2 = 3 cm.
    2. Find the area of the rectangle:
      Arect=10×6=60 cm2A_{\text{rect}} = 10 \times 6 = 60 \text{ cm}^2
    3. Find the area of the semicircle:
      Asemi=12πr2=12×π×32=9π2≈14.1 cm2A_{\text{semi}} = \frac{1}{2}\pi r^2 = \frac{1}{2} \times \pi \times 3^2 = \frac{9\pi}{2} \approx 14.1 \text{ cm}^2
    4. Add the areas:
      Atotal=60+14.1=74.1 cm2A_{\text{total}} = 60 + 14.1 = 74.1 \text{ cm}^2

    Answer: Total area ≈74.1\approx 74.1 cm2^2

  3. Example 3 · Real-world problem: circular garden border

    A gardener wants to put a circular garden bed in a park. The garden bed has a radius of 33 m, and there is a circular path 11 m wide that runs around the outside of it, forming a larger circle with radius 44 m. The garden bed will be planted with flowers, and the path will be paved. Find the area of the path only, correct to two decimal places.

    Show worked solution

    Key idea: The path is an annulus (a ring shape). Its area equals the area of the large circle minus the area of the small circle.

    1. Write the radii: outer radius R=4R = 4 m, inner radius r=3r = 3 m.
    2. Find the area of the large circle:
      Alarge=πR2=π×42=16π m2A_{\text{large}} = \pi R^2 = \pi \times 4^2 = 16\pi \text{ m}^2
    3. Find the area of the small circle:
      Asmall=πr2=π×32=9π m2A_{\text{small}} = \pi r^2 = \pi \times 3^2 = 9\pi \text{ m}^2
    4. Find the area of the path:
      Apath=16π−9π=7π≈21.99 m2A_{\text{path}} = 16\pi - 9\pi = 7\pi \approx 21.99 \text{ m}^2

    Answer: The area of the path is ≈21.99\approx 21.99 m2^2

Common mistakes

Where students usually lose marks

Confusing radius and diameter

Diameter =10= 10 cm, so A=π×102=100πA = \pi \times 10^2 = 100\pi cm2^2

Always halve the diameter before substituting into A=πr2A = \pi r^2 or C=2πrC = 2\pi r. Here r=5r = 5 cm, so A=π×52=25πA = \pi \times 5^2 = 25\pi cm2^2.

Forgetting to square the radius when finding area

A=π×6=6πA = \pi \times 6 = 6\pi cm2^2 (with r=6r = 6 cm)

The area formula is A=πr2A = \pi r^2, so you must square rr first. With r=6r = 6 cm: A=π×62=36πA = \pi \times 6^2 = 36\pi cm2^2.

Using the wrong fraction for a semicircle or quadrant

Area of a quadrant =12πr2= \frac{1}{2}\pi r^2

A semicircle is half a circle (12πr2\frac{1}{2}\pi r^2) and a quadrant is a quarter of a circle (14πr2\frac{1}{4}\pi r^2). Always think about what fraction of the full circle you have.

Subtracting areas the wrong way around for an annulus

Area of annulus =πrsmall2−πRlarge2= \pi r_{\text{small}}^2 - \pi R_{\text{large}}^2

Always subtract the smaller (inner) area from the larger (outer) area: A=πR2−πr2A = \pi R^2 - \pi r^2. Doing it backwards gives a negative answer, which is impossible for an area.

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Your turn

A circular garden has a diameter of 8 m. What is the area of the garden in square metres, correct to 2 decimal places?

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About this worksheet

Why we built it

Year 8 is where students apply pi to both circumference and area of circles, and start handling composite shapes (semicircles, quadrants, annulus). These worksheets give your student practice on each variation - exact, decimal and word-problem answers - so the formulas stay in long-term memory.

What's covered

Sub-skills your student will practise

  • ✓Circumference using diameter or radius
  • ✓Area of a circle from radius or diameter
  • ✓Working back from an area or circumference to find the radius
  • ✓Composite shapes (semicircles, quadrants, annulus)
  • ✓Real-world circle problems (running tracks, gardens, pizzas)

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Frequently asked

Questions parents ask about circles

What's the difference between circumference and area of a circle?

Circumference is the distance around the circle (the perimeter). Area is the space inside. Different formulas: C = pi x d for circumference, A = pi x r^2 for area.

Why is the area formula pi r squared?

If you imagine slicing a circle into thin wedges and rearranging them, they approximate a rectangle with height equal to the radius and width equal to half the circumference. So area = r x (1/2 x 2 x pi x r) = pi x r^2.

What does Year 8 do with composite shapes?

Year 8 introduces composite shapes like semicircles, quadrants, and annulus (a ring shape). Students learn to add and subtract circle parts from rectangles or each other - a key skill for SAC questions.

Are exact (in terms of pi) answers acceptable?

Yes - many Year 8 questions specifically ask for an exact answer in terms of pi (e.g., 16 pi cm^2). Decimal answers are also accepted, usually to 1 or 2 decimal places.

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