Year 9 - Surface area and volume - Free practice

Year 9 Surface Area & Volume Worksheets

Cylinders, prisms, composite 3D objects.

Quick answer

How do you find the surface area and volume of prisms and cylinders?

Add the areas of every face for surface area, or multiply the base area by the height for volume. For a cylinder: surface area = 2πr² + 2πrh and volume = πr²h. For a rectangular prism with length 5 cm, width 3 cm and height 4 cm: volume = 5 × 3 × 4 = 60 cm³.

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Worked examples

Year 9 surface area and volume: worked examples

Three examples, from a standard question to a worded problem. Have a go at each one before you open the solution.

  1. Example 1 · Surface area of a cylinder

    A cylinder has a radius of 44 cm and a height of 1010 cm. Find its total surface area. Give your answer correct to one decimal place.

    Show worked solution

    Key idea: The total surface area of a cylinder is the curved surface (a rectangle when unrolled) plus two circular ends: TSA=2πrh+2πr2\text{TSA} = 2\pi r h + 2\pi r^2.

    1. Write the formula: TSA=2πrh+2πr2\text{TSA} = 2\pi r h + 2\pi r^2
    2. Substitute r=4r = 4 and h=10h = 10:
      TSA=2π(4)(10)+2π(4)2\text{TSA} = 2\pi(4)(10) + 2\pi(4)^2
    3. Simplify each term:
      TSA=80π+32π=112π\text{TSA} = 80\pi + 32\pi = 112\pi
    4. Evaluate:
      TSA=112π≈351.9 cm2\text{TSA} = 112\pi \approx 351.9 \text{ cm}^2

    Answer: 351.9351.9 cm²

  2. Example 2 · Volume of a composite solid (prism and cylinder)

    A composite solid is made by placing a cylinder on top of a rectangular prism. The rectangular prism has a length of 1212 cm, a width of 1212 cm and a height of 88 cm. The cylinder sits centred on top and has a radius of 33 cm and a height of 55 cm. Find the total volume of the solid. Give your answer correct to one decimal place.

    Show worked solution

    Key idea: The total volume of a composite solid is the sum of the volumes of each part: Vtotal=Vprism+VcylinderV_{\text{total}} = V_{\text{prism}} + V_{\text{cylinder}}.

    1. Find the volume of the rectangular prism:
      Vprism=l×w×h=12×12×8=1152 cm3V_{\text{prism}} = l \times w \times h = 12 \times 12 \times 8 = 1152 \text{ cm}^3
    2. Find the volume of the cylinder:
      Vcylinder=πr2h=π×32×5=45π cm3V_{\text{cylinder}} = \pi r^2 h = \pi \times 3^2 \times 5 = 45\pi \text{ cm}^3
    3. Add the two volumes:
      Vtotal=1152+45π≈1152+141.4=1293.4 cm3V_{\text{total}} = 1152 + 45\pi \approx 1152 + 141.4 = 1293.4 \text{ cm}^3

    Answer: 1293.41293.4 cm³

  3. Example 3 · Real-world problem: painting a room

    Mia wants to paint the four walls and the ceiling of a rectangular room. The room is 66 m long, 44 m wide and 2.52.5 m high. The room has one door measuring 22 m by 0.90.9 m and one window measuring 1.21.2 m by 11 m, which are not painted. One litre of paint covers 1212 m² and costs $8.50. How much will Mia spend on paint? Round up to the nearest whole litre when buying paint.

    Show worked solution

    Key idea: Find the total area to be painted by calculating the area of all four walls and the ceiling, then subtract the unpainted door and window. Use the coverage rate to find litres needed, then calculate the cost.

    1. Find the area of the four walls:
      Awalls=2(lh+wh)=2(6×2.5+4×2.5)=2(15+10)=50 m2A_{\text{walls}} = 2(lh + wh) = 2(6 \times 2.5 + 4 \times 2.5) = 2(15 + 10) = 50 \text{ m}^2
    2. Find the area of the ceiling:
      Aceiling=6×4=24 m2A_{\text{ceiling}} = 6 \times 4 = 24 \text{ m}^2
    3. Subtract the door and window:
      Apainted=50+24−(2×0.9)−(1.2×1)=74−1.8−1.2=71 m2A_{\text{painted}} = 50 + 24 - (2 \times 0.9) - (1.2 \times 1) = 74 - 1.8 - 1.2 = 71 \text{ m}^2
    4. Find litres needed, rounding up:
      Litres=⌈71÷12⌉=⌈5.916…⌉=6 L\text{Litres} = \lceil 71 \div 12 \rceil = \lceil 5.916\ldots \rceil = 6 \text{ L}
    5. Calculate the cost:
      Cost=6×$8.50=$51.00\text{Cost} = 6 \times \$8.50 = \$51.00

    Answer: $51.00

Common mistakes

Where students usually lose marks

Using diameter instead of radius

Cylinder with diameter 88 cm: V=π×82×hV = \pi \times 8^2 \times h ✗

Always halve the diameter before substituting into a formula. If the diameter is 88 cm, the radius is r=4r = 4 cm, so use r=4r = 4 in V=πr2hV = \pi r^2 h and TSA=2πrh+2πr2\text{TSA} = 2\pi r h + 2\pi r^2.

Forgetting the two circular ends on a cylinder

TSA=2πrh\text{TSA} = 2\pi r h only ✗

A closed cylinder has three faces: one curved surface and two circular ends. The full formula is TSA=2πrh+2πr2\text{TSA} = 2\pi r h + 2\pi r^2. If the cylinder is open at one or both ends (such as a pipe), adjust accordingly, but always check the question.

Adding surface areas instead of volumes for composite solids

Vtotal=TSA1+TSA2V_{\text{total}} = \text{TSA}_1 + \text{TSA}_2 ✗

For the total volume of a composite solid, add the volumes of each part: Vtotal=V1+V2V_{\text{total}} = V_1 + V_2. Surface area and volume are different measures. Be careful not to mix them up, especially when a question asks specifically for volume.

Not subtracting the joined face in composite surface area problems

TSA=TSA1+TSA2\text{TSA} = \text{TSA}_1 + \text{TSA}_2 without removing the shared face ✗

When two solids are joined face-to-face, that shared face is hidden and is no longer part of the outer surface. Subtract the area of the shared face once from each solid, so subtract it twice in total: TSA=TSA1+TSA2−2×Ashared\text{TSA} = \text{TSA}_1 + \text{TSA}_2 - 2 \times A_{\text{shared}}.

Try one yourself

Your turn

A cylindrical tin has a radius of 4 cm and a height of 10 cm. What is the total surface area of the tin, correct to 2 decimal places, in cm²?

Got a different surface area and volume question wrong? Upload it to Tuterly and get the worked solution and a fresh one to practise, free.

About this worksheet

Why we built it

Year 9 takes 3D measurement up a level - cylinders, composite prisms, and surface area for the first time. These worksheets give your student varied 3D objects so they get comfortable identifying which formula applies to which face.

What's covered

Sub-skills your student will practise

  • ✓Surface area of right prisms (rectangular, triangular)
  • ✓Surface area of cylinders (curved + two circles)
  • ✓Volume of cylinders
  • ✓Composite solids (prism + prism, prism + cylinder)
  • ✓Real-world problems (paint, packaging, capacity)

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Frequently asked

Questions parents ask about surface area and volume

What's the surface area of a cylinder?

Two circles (top and bottom) plus the curved side, which unrolls into a rectangle. So SA = 2 x pi x r^2 + 2 x pi x r x h. The 2 x pi x r is the circumference, which becomes the width of the unrolled rectangle.

How is Year 9 SA harder than Year 8?

Year 9 includes cylinders (curved surfaces) and composite solids (a cylinder on top of a rectangular prism, say). Students have to think about which faces are hidden inside the join and not counted.

What's the volume formula for a cylinder?

V = pi x r^2 x h - the area of the circular base times the height. Same pattern as a prism: cross-section area times length.

How do students approach a composite solid?

Split it into individual shapes, calculate the volume or SA of each, then add (for volume) or subtract any hidden faces (for SA). The hidden-face check is what catches Year 9 students out.

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