Year 10 maths · Chapter 4

Year 10 Measurement and surds: revision mind map

Surds and rationalising the denominator, length, Pythagoras in 3D, area, measurement error, and surface area and volume of prisms, cylinders, pyramids, cones and spheres. Everything on one A4 page.

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1Irrational numbers and surds

A surd is a root that isn't a whole number, like 2\sqrt2. Simplify using square factors.

8=22\sqrt8 = 2\sqrt2   48=163=43\sqrt{48} = \sqrt{16}\sqrt3 = 4\sqrt3

2Operations with surds

Add and subtract like surds only. Multiply or divide the numbers outside and inside separately.

12+27=23+33=53\sqrt{12} + \sqrt{27} = 2\sqrt3 + 3\sqrt3 = 5\sqrt3

6×3=18=32\sqrt6 \times \sqrt3 = \sqrt{18} = 3\sqrt2   610÷25=326\sqrt{10} \div 2\sqrt5 = 3\sqrt2

3Rationalising the denominator

Multiply top and bottom so there's no surd on the bottom.

32=322\dfrac{3}{\sqrt2} = \dfrac{3\sqrt2}{2}

13+1×3−13−1=3−12\dfrac{1}{\sqrt3 + 1} \times \dfrac{\sqrt3 - 1}{\sqrt3 - 1} = \dfrac{\sqrt3 - 1}{2}

4Review of length

Circumference 2πr2\pi r. Arc length θ360×2πr\tfrac{\theta}{360} \times 2\pi r.

r=10, θ=72∘r = 10,\ \theta = 72^\circ: arc 15×20π=4π≈12.57\tfrac15 \times 20\pi = 4\pi \approx 12.57

5Pythagoras in 3D

Find a right triangle, or use d=a2+b2+c2d = \sqrt{a^2 + b^2 + c^2} for a box.

Box 2 by 3 by 6: 4+9+36=7\sqrt{4 + 9 + 36} = 7

6Review of area

Triangle 12bh\tfrac12 bh, trapezium 12(a+b)h\tfrac12(a + b)h, circle πr2\pi r^2, sector θ360πr2\tfrac{\theta}{360}\pi r^2

Sector r=6, θ=60∘r = 6,\ \theta = 60^\circ: 16×36π=6π≈18.85\tfrac16 \times 36\pi = 6\pi \approx 18.85

7Measurement errors and accuracy

The error is up to half the smallest unit. Percentage error = error ÷ measurement × 100%.

4.2 m to the nearest 0.1 m: between 4.15 m and 4.25 m

Percentage error 0.054.2×100%≈1.2%\tfrac{0.05}{4.2} \times 100\% \approx 1.2\%

8Surface area: prisms and cylinders

Add every face. Cylinder: 2πr2+2πrh2\pi r^2 + 2\pi rh.

Cylinder r=4, h=10r = 4,\ h = 10: 32π+80π=112π≈351.932\pi + 80\pi = 112\pi \approx 351.9

9Surface area: pyramids and cones

Cone: πr2+πrs\pi r^2 + \pi r s, where ss is the slant height.

r=3, h=4r = 3,\ h = 4: s=5s = 5, so SA=9π+15π=24π≈75.4SA = 9\pi + 15\pi = 24\pi \approx 75.4

Watch out: use the slant height, not the vertical height.

10Volume: prisms and cylinders

V=AhV = Ah. Cylinder: V=πr2hV = \pi r^2 h.

r=5, h=8r = 5,\ h = 8: V=200π≈628.3V = 200\pi \approx 628.3

11Volume: pyramids and cones

V=13AhV = \tfrac13 Ah: a third of the matching prism.

Cone r=3, h=4r = 3,\ h = 4: 13×9π×4=12π≈37.7\tfrac13 \times 9\pi \times 4 = 12\pi \approx 37.7

Square pyramid, base 6, height 10: 13×36×10=120\tfrac13 \times 36 \times 10 = 120

12Spheres

SA=4πr2SA = 4\pi r^2 and V=43πr3V = \tfrac43 \pi r^3

r=6r = 6: SA=144π≈452.4SA = 144\pi \approx 452.4

V=43π(216)=288π≈904.8V = \tfrac43\pi(216) = 288\pi \approx 904.8

Year 10 maths · Chapter 4 · Mind map

Measurement and surds

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In this chapter

  • 4A Irrational numbers and surds
  • 4B, 4C Operations with surds
  • 4D Rationalising the denominator
  • 4E Review of length
  • 4F Pythagoras in 3D
  • 4G Review of area
  • 4H Measurement errors and accuracy
  • 4I Surface area: prisms and cylinders
  • 4J Surface area: pyramids and cones
  • 4K Volume: prisms and cylinders
  • 4L Volume: pyramids and cones
  • 4M Spheres

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