Maths explained · Years 7 to 10

How to find the circumference of a circle

The circumference is the distance all the way around a circle: its perimeter. You can find it from the radius or the diameter, and the same idea gives you the perimeter of a semicircle and the length of an arc. Here’s each one with a worked example, a calculator that shows the working, and practice questions with answers.

Quick answer

Circumference = π × diameter, or 2 × π × radius: C = πd = 2πr. Use the π button on your calculator (π ≈ 3.14159). Circumference is a length, so it’s in plain units like cm or m. To work backwards, the diameter is C ÷ π.

Stuck on a circumference question?

Snap it. Tuterly shows a detailed worked solution, then gives fresh questions on the same skill until you can do it on your own. Years 7 to 10.

Coming soon on iPhone. Android soon after.

Launch price: 50% off until 31 March 2027. $17.99 $8.99 a week or $59.99 $29.99 a month.

We'll email you when Tuterly launches, plus occasional maths tips and offers. Unsubscribe any time. See our privacy policy.

Free to download · Years 7 to 10 maths · On iPhone. Android coming soon

The circumference formula

C=πd=2πrC = \pi d = 2\pi r

π\pi is the number you get when you divide any circle's circumference by its diameter: about 3.141593.14159. That's why C=πdC = \pi d. Because the diameter is two radii, C=2πrC = 2\pi r is the same formula.

  • Given the diameter: multiply by π\pi.
  • Given the radius: multiply by 22, then by π\pi.

Circumference from the radius or diameter

Worked example: from the radius

Find the circumference of a circle with radius 44 cm.

C=2πr=2×π×4=8πC = 2\pi r = 2 \times \pi \times 4 = 8\pi C≈25.13 cmC \approx 25.13 \text{ cm}

Worked example: from the diameter

Find the circumference of a circle with diameter 1515 m.

C=πd=π×15=15πC = \pi d = \pi \times 15 = 15\pi C≈47.12 mC \approx 47.12 \text{ m}

8π8\pi cm is the exact answer; 25.1325.13 cm is rounded to 2 decimal places.

Circumference calculator (with working)

Enter the radius, diameter, circumference or area. You’ll get all four, with the exact answer in terms of π where it’s tidy and decimals rounded to 2 decimal places.

rd

Circumference = 10π ≈ 31.42 cm

  • Radius = 5 cm
  • Diameter = 10 cm
  • Circumference = 10π ≈ 31.42 cm
  • Area = 25π ≈ 78.54 cm²
  1. Radius: r=5 cmr = 5\text{ cm}
  2. Diameter: d=2r=2×5=10 cmd = 2r = 2 \times 5 = 10\text{ cm}
  3. Circumference: C=2πr=πd=π×10=10π≈31.42 cmC = 2\pi r = \pi d = \pi \times 10 = 10\pi \approx 31.42\text{ cm}
  4. Area: A=πr2=π×52=25π≈78.54 cm2A = \pi r^2 = \pi \times 5^2 = 25\pi \approx 78.54\text{ cm}^2
  5. Decimal answers are rounded to 2 decimal places using the π button. If your teacher says to use 3.14, your answer may be slightly different.

Pick what you know and enter it. Area units are squared (cm²), lengths are not.

Perimeter of a semicircle and a quarter circle

The perimeter is the whole way around the shape, so include the straight edges as well as the curved part.

semicircle: P=12πd+d\text{semicircle: } P = \frac{1}{2}\pi d + d

Worked example

Find the perimeter of a semicircle with diameter 1010 cm.

curved part=12×π×10=5π\text{curved part} = \frac{1}{2} \times \pi \times 10 = 5\pi P=5π+10≈25.71 cmP = 5\pi + 10 \approx 25.71 \text{ cm}

Worked example: quarter circle

Find the perimeter of a quarter circle with radius 66 cm.

curved part=14×2π×6=3π\text{curved part} = \frac{1}{4} \times 2\pi \times 6 = 3\pi P=3π+6+6=3π+12≈21.42 cmP = 3\pi + 6 + 6 = 3\pi + 12 \approx 21.42 \text{ cm}

Arc length and the perimeter of a sector (Years 9 and 10)

An arc is part of the circumference. If the angle at the centre is θ\theta degrees, the arc is θ360\dfrac{\theta}{360} of the whole circumference.

l=θ360×2πrl = \frac{\theta}{360} \times 2\pi r

Worked example

A sector has radius 88 cm and angle 45∘45^\circ. Find the arc length and the perimeter of the sector.

l=45360×2×π×8=18×16π=2π≈6.28 cml = \frac{45}{360} \times 2 \times \pi \times 8 = \frac{1}{8} \times 16\pi = 2\pi \approx 6.28 \text{ cm} P=l+2r=2π+16≈22.28 cmP = l + 2r = 2\pi + 16 \approx 22.28 \text{ cm}

The perimeter of a sector is the arc plus the two radii. Forgetting the radii is the most common mistake.

How to find the radius or diameter from the circumference

d=Cπr=C2πd = \frac{C}{\pi} \qquad r = \frac{C}{2\pi}

Worked example

A circle has a circumference of 5050 cm. Find its diameter and radius.

d=50π≈15.92 cmd = \frac{50}{\pi} \approx 15.92 \text{ cm} r=502π≈7.96 cmr = \frac{50}{2\pi} \approx 7.96 \text{ cm}

Wheels and distance

Each full turn of a wheel moves it forward one circumference.

Worked example

A bike wheel has a diameter of 6060 cm. How far does the bike travel in 100100 full turns?

C=π×60=60π cmC = \pi \times 60 = 60\pi \text{ cm} 100×60π=6000π≈18 849.56 cm100 \times 60\pi = 6000\pi \approx 18\,849.56 \text{ cm}

That's about 188.50188.50 m.

Common mistakes

  • Using πr\pi r instead of 2πr2\pi r. With the radius you must double it (or use πd\pi d).
  • Doubling the diameter. C=πdC = \pi d already uses the full width. Don't multiply by 2 again.
  • Mixing up circumference and area. Circumference is 2πr2\pi r in cm. Area is πr2\pi r^2 in cm².
  • Leaving out straight edges. The perimeter of a semicircle or sector includes the diameter or the two radii.

Practice questions with answers

Try each one before you open the answer. Decimal answers use the π button and are rounded to 2 decimal places.

  1. Find the circumference of a circle with radius 77 cm.

    Show the answer

    C=2×π×7=14π≈43.98C = 2 \times \pi \times 7 = 14\pi \approx 43.98 cm

  2. Find the circumference of a circle with diameter 2020 m.

    Show the answer

    C=π×20=20π≈62.83C = \pi \times 20 = 20\pi \approx 62.83 m

  3. Find the circumference of a circle with radius 3.53.5 mm.

    Show the answer

    C=2×π×3.5=7π≈21.99C = 2 \times \pi \times 3.5 = 7\pi \approx 21.99 mm

  4. Find the perimeter of a semicircle with diameter 88 cm.

    Show the answer

    Curved part: 12×π×8=4π\dfrac{1}{2} \times \pi \times 8 = 4\pi. Add the diameter: P=4π+8≈20.57P = 4\pi + 8 \approx 20.57 cm

  5. Find the arc length of a sector with radius 1010 cm and angle 90∘90^\circ.

    Show the answer

    l=90360×2π×10=5π≈15.71l = \dfrac{90}{360} \times 2\pi \times 10 = 5\pi \approx 15.71 cm

  6. A circle has a circumference of 100100 cm. Find its diameter and radius.

    Show the answer

    d=100π≈31.83d = \dfrac{100}{\pi} \approx 31.83 cm, so r≈15.92r \approx 15.92 cm

  7. Find the perimeter of a sector with radius 1212 m and angle 60∘60^\circ.

    Show the answer

    Arc: 60360×2π×12=4π\dfrac{60}{360} \times 2\pi \times 12 = 4\pi. Add the two radii: P=4π+24≈36.57P = 4\pi + 24 \approx 36.57 m

Circumference by year level

Following the Victorian Curriculum 2.0. Schools sequence topics differently, so check your course.

Year 7

Circles

Radius, diameter, π, and the circumference from the radius or diameter.

Year 8

Circles

Circumference and area problems, working back to the radius, and semicircles and quadrants.

Year 8

Area and perimeter

Perimeter of composite shapes, including where some sides need calculating first.

Year 9

Surface area and volume

The circumference inside the curved surface area of a cylinder, 2πrh.

Circumference: common questions

What is the formula for circumference?

C = πd, or C = 2πr. Both give the same answer, because the diameter is twice the radius. A circle with radius 4 cm has circumference 8π ≈ 25.13 cm.

What's the difference between circumference and area?

Circumference is the distance around the edge of the circle, measured in plain units like cm. Area is the space inside, measured in square units like cm². Circumference uses 2πr; area uses πr².

How do I find the diameter from the circumference?

Divide the circumference by π: d = C ÷ π. Halve that for the radius. If C = 50 cm, d = 50 ÷ π ≈ 15.92 cm and r ≈ 7.96 cm.

How do I find the perimeter of a semicircle?

Add half the circumference to the straight edge (the diameter): P = ½πd + d. For a diameter of 10 cm, P = 5π + 10 ≈ 25.71 cm.

What year level learns circumference?

In the Victorian Curriculum 2.0, Year 7 covers π and the relationship between the circumference, radius and diameter. Year 8 uses the formulas to solve problems, including composite shapes. Arc length is often taught in Year 9 or 10, depending on the school.

Tuterly · Years 7 to 10 maths

Got a circle question wrong in homework?

Snap it with Tuterly. You’ll see every step of the working, then get fresh questions on the same skill until it’s mastered. Built for the Australian Curriculum by Bayside Academics.

Coming soon on iPhone. Android soon after.

Launch price: 50% off until 31 March 2027. $17.99 $8.99 a week or $59.99 $29.99 a month.

We'll email you when Tuterly launches, plus occasional maths tips and offers. Unsubscribe any time. See our privacy policy.

Free to download · Years 7 to 10 maths · On iPhone. Android coming soon
Or try it free now with your own question →